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Solving for the end effector is done by using links 4 and 5 as building block vectors, defining point A as origin, and defining point C as a function of θ2.
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width | 50 |
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test
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width | 10% |
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test2
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border | true |
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....................................................................................(Eq. 5)
..................................................
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.................................(Eq.
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6)
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.............................(Eq. 7)
...........................................(Eq.
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8)