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Derivation

MA =
\begin{vmatrix}
\frac{\omega_{crank}}{\omega_{out}}
\end{vmatrix}
\begin{vmatrix}
\frac{r_{crank}}{r_{out}}
\end{vmatrix}

The mechanical advantage of a system is defined by:

Image Added ..........................................................................(Eq. 11)

For my case, the input radius  and angular velocity comes from the crank itself, not link 2. The output angular velocity can either be ω4 or ω5. The output radius is the same for link 4 and link 5.

Image Added ............................................................(Eq. 12)

I have solved for the angular velocity ratio for | ω2 / ωout | in the previous section. We can thereby solve for the equivalent angular velocity ratio for | ωcrank / ωout |:

Image Added.........................................................(Eq. 13)

Image Added................................................................................(Eq. 14)

Substituting equation 13 and equation 14 to equation 12 gives:

Image Added........................................(Eq. 15)


Finally the total mechanical advantage is the summation of both end effector forces:

Image Added.................(Eq. 16)

Plot

Image Added