...
| Latex formatting |
|---|
$$h = \frac{1}{2mg}\kappa\Delta\theta^2$$theta^2}{2mg}$$ |
where h is the jump height, m is the mass, κ is the spring constant and Δθ is the spring's deflection angle. From a rough estimate, we found that our mechanism should jump ~30cm, however, we only realized ~5-10cm of jump height. Some future iterations to improve upon would be to:
...