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Design:

The motor controller will be screwed (M4) onto a heat sink which will be enclosed by a multi print 3-D printed (cracks sealed with JB weld) ASA enclosure with splash proof connectors and lid. The heat sink will need to be cut and drilled.

https://pdm.getbild.com/0d9d31f0-3579-4fcd-82a8-b5347c436243/branch/main?tab=project_files&dir=f10bac09-82af-4c70-a506-89a20340b9d5

Motor Controller Datasheet:

https://docs.prohelion.com/Motor_Controllers/WaveSculptor22/User_Manual/Cooling.html

Dimensions

Heat Sink Selected:

https://www.digikey.com/en/products/detail/advanced-thermal-solutions-inc/ATS-EXL6-254-R0/5848412

Fans Selected:

https://www.coolerguys.com/products/coolerguys-80mm-80x80x25-3500-rpm-ip67-12v-high-airflow-fan-cg8025h12-ip67?srsltid=AfmBOooDff47oTqTYFHEbanlRrF9SSYE0-6a3lNzms3B6DFb-6ESckKM

Enclosure Connector:

https://amphenol-industrial.com/products/epower-lite-and-epower-lite-mini/

Calculations:

Ploss = ReqIo2 + (αIo + β)Vbus + C𝑓eqVbus2 (from datasheet)

Req= 1.0800E-2, 𝛼= 3.3450E-3, β= 1.8153E-2, C𝑓eq= 1.5625E-4

Vbus = 134.4V (battery 100% SOC), Io = 60/sqrt(2) A (rms value)

Ploss = 43.7757W (heat generated)

We can assume that all of the power loss will be converted to heat, therefore the heat generated will be considered 43.78W. For the sake of simplicity, we are also assuming all of this heat is being transferred to the heat sink attached to the motor controller. Also, the airflow will not be evenly distributed across each fin with the two fans, but for the sake of simplicity we are assuming it is.

Q = hAtotal​(Tobject−Tambient) (Newton’s Law of Cooling)

Atotal = (((2 fin height length) number of fins) + (length width) (0.592m²)

Pr = 0.71 (Prandtl number for air)

Re = ρvL/μ​ (Reynold’s number)

v = 4.16m/s (Air velocity caused by fans, I used a an online calculator )

  • ρ is the air density (typically 1.2 kg/m³ at room temperature).

  • v is the airflow velocity (m/s), which can be estimated from the fan's specifications.

  • L is a characteristic length (0.250m)

  • μ is the dynamic viscosity of air (1.918E-5 kg/ms)

Nu = 0.023 ⋅ Re0.8 ⋅ Pr0.33 ⋅ (L/D​)0.5 (Nusselt’s number for airflow parallel to fins)

  • L = Length of the fin (in the direction of the flow, 0.250m)

  • D = Characteristic dimension (fin height, 0.027m)

Nu = hL/k

  • h: is the heat transfer coefficient 

  • L: is the characteristic length (0.250m)

  • k: is the thermal conductivity air (0.026 W/mk)

h = (0.023 ⋅ Re0.8 ⋅ Pr0.33 ⋅ (L/D​)0.5 ⋅ k)/L

Q = ((0.023 ⋅ Re0.8 ⋅ Pr0.33 ⋅ (L/D​)0.5 ⋅ k)/L)Atotal​(Tobject−Tambient)

Q = ((0.023 ⋅ ρvL/μ​0.8 ⋅ Pr0.33 ⋅ (L/D​)0.5 ⋅ k)/L)Atotal​(Tobject−Tambient) (heat transferred)

Q = 27.2885 ⋅ ΔT

Q = 8.9679 ⋅ ΔT

Sources:

https://www.engineeringtoolbox.com/air-prandtl-number-viscosity-heat-capacity-thermal-conductivity-d_2009.html

https://www.engineersedge.com/physics/viscosity_of_air_dynamic_and_kinematic_14483.htm

Nusselt number and the factors influencing it for perforated fin array of different shapes

https://www.nuclear-power.com/nuclear-engineering/heat-transfer/convection-convective-heat-transfer/dittus-boelter-equation/

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